Object assignment

David, you might want to read through <http://www.php.net/manual/en/language.oop5.php> for a better undrestanding of objects in PHP5 in general.

But specifically for your question - please note that object variables are always pointers to objects.  A variable never is the object itself - only a pointer to one.

Therefore, $objCopy = $objMyObject does not make a copy of MyObject.  It only makes a copy of the pointer to the object pointed to by $objMyObject in $objCopy.  Or in other words, $objCopy and $objMyObject are now pointing to the same exact object.

$objCopy2 = &$objMyObject is just not a good idea.  And I actually have no idea what it will do.

If you want to make a copy of an object, you should use clone(): <http://www.php.net/manual/en/language.oop5.cloning.php>.  All the warnings about cloning objects with pointers to resources doesn't really apply here.  Data class objects in your qcodo code-generated ORM are freestanding.

HOWEVER -- note that a cloned object will still have the exact same Primary Key ID as the object that you copied.  So it will still refer to the exact same row in the database.

Hi folks

But if I made the following operation

 $objOne = Person::Load(1);
 $objTwo = new Person();
 $objTwo = $objOne;
 $objTwo->Id = 2;
 $objTwo->Save();

My idea is only change the key info. if exist a best way to do this please drop a post.

Best regards.

Funny, I just came across the need to do use the clone() PHP function for the first time in a long, long time. And just like David B says, I've done a ->Save(true) to do a “force insert”.

I'm wondering if a tiny addition of

public function __clone() {
    $this->Save(true); // re-save, forcing insert
}

into the Codegen templates would save someone 10 minutes of a headache. Mike?

You're totally right. I take my suggestion back :)

There IS this functionality in the core. It's called Save(true), instead of __clone(), but it's there... If the function name is important to you, you can write your own wrapper function into the templates.