Adding QForm instance to the cell of a QDataGrid

Unfortunately, no... but what functionality were you hoping to achieve by putting individual QForms into a DataGrid?

Usually, the same functionality can be had by using custom QPanels.  You can certainly place individual QPanels into a QDataGrid.

There is a specific examples page that discusses this in detail at http://examples.qcodo.com/examples/multiple_qform/intro.php

Conrad,

This answer is also for the questions you posted in this thread.

I think a semantic precision has to be made here, for you can't have a QForm within a QDatagrid. QCodo only generates one FORM tag which somehow corresponds to the RenderBegin function in the template file. If I understand your question well, you want to have a QTextBox and a QButton within each row of a QDatagrid. Check out this example to achieve this : http://examples.qcodo.com/examples/dynamic/inline_editing.php. Hope this helps.

As for your issue “Accompanying HTML Include File does not exist”, you also need to edit your template file and edit the path at the bottom of your form which should look like this : YourFormName::Run('YourFormName', 'path/to/your/template/file/your_template.tpl.php');

patrick

You are on the good path. The only thing is that you should render your QTextBox and QButton in 2 seperate columns, or at least by calling 2 seperate functions like this :

   public function TextBox_Render( Item $objItem ) {
     
     $strControlIdTextField = 'TextField' . $objAuctionItem->Id;
     
     // Let's see if the TextBox exists already.
     $TextField = $this->GetControl(  $strControlIdTextField );

     
     if ( !$TextField) {
        // Create the text field.
       $TextField = new QTextBox( $this, $strControlIdTextField ); 
     }
     
     // return the TextBox
     return $TextField->Render( false );
     
   }
   
   
   public function SaveButton_Render( Item $objItem ) {
     
     $strControlIdButton    = 'Button' . $objAuctionItem->Id;
     
     // Let's see if the button exists already.
     $Button = $this->GetControl(  $strControlIdButton );
     
     if ( !Button ) {
       // Create the button.
       $Button = new QButton( $this, $strControlIdButton );
       $Button->Text = 'Place Presale Bid?';
       $Button->Visible = true;
     }
     
    // Return the Button
     return $Button->Render( false );
     
   }
   

Let me know how it works out.

-Patrick

Just add a QConfirmAction before the QServerAction that saves the form :

 if ( !$Button ) {
     // Create the button.
     $Button = new QButton( $this, $strControlIdButton );
     $Button->Text = 'Enter amount?';
     $Button->Visible = true;
     $Button->AddAction(new QClickEvent(), new QConfirmAction('Your message here'));
     $Button->AddAction( new QClickEvent(), new QServerAction( 'Button_Click' ) );
     $Button->CausesValidation = true;
}

For Form_Validate() to be fired, it depends on your architecture.  I guess since your button is within your datagrid, you need to access the Form_Validate() function of the parent object. Although I have never done this, I think you need to add $Button->CausesValidation = $this->objParentControl;. If from within the Form_Validate() function you want to access the value submitted, I think you need to access it with $this->YourDatagridObject->GetChildControl($controlID). Tell me about it.

-Patrick

Yeah I think a misleaded you on this one. I'll try to give you a more complete answer here.

In the first place when you create your textboxes, you should have an array of textboxes so that you can access them later out of the scope of your function. Instead of

$TextField = new QTextBox( $this, $strControlIdTextField ); 

you would first declare a variable (in the form itself, not in a function), something like

protected $TextFieldArray;

and then when you create your textbox (note that the datagrid is the parent, not the form):

$this->TextFieldArray[$strControlIdTextField ] = new QTextBox($this->dtgItem, $strControlIdTextField ); 

Same thing when you create your button, but then you will add an ActionParameter to your button :

 if ( !$Button ) {
     // Create the button.
     $this->ButtonArray[strControlIdButton] = new QButton($this->dtgItem, $strControlIdButton );
     $this->ButtonArray[strControlIdButton]->ActionParameter = $strControlIdButton;
     $this->ButtonArray[strControlIdButton]->Text = 'Enter amount?';
     $this->ButtonArray[strControlIdButton]->Visible = true;
     $this->ButtonArray[strControlIdButton]->AddAction(new QClickEvent(), new QConfirmAction('Your message here'));
     $this->ButtonArray[strControlIdButton]->AddAction( new QClickEvent(), new QServerAction( 'Button_Click' ) );
     $this->ButtonArray[strControlIdButton]->CausesValidation = true;
}

Next, when you want to get the value of one of your TextFieldArray item, your function has to receive the parameters that are automatically send when your button is clicked and that you can optionally use.

protected function TextField_Save ($strFormId, $strControlId, $strParameter) {

 $strValueEntered = $this->TextFieldArray[$strParameter]->Text;
 
 $objItem = Item::LoadByItemId($strParameter);
 
 $objItem->YourDBfield = $strValueEntered;
 $objItem->Save();
   
}

Just a precision on $_ITEM : you can only access it within the scope of your Datagrid. Meaning if you want to use it outside of this scope, you need to pass it to the function you are calling from your datagrid column declaration, like this : $_FORM->SaveButton_Render($_ITEM). Then, your function SaveButton_Render ( Item $objItem ) can receive the the object and you can use $objItem->YourobjDBfield.

Hope this helps. Sorry for rounding corners in my previous posts.

-patrick